ME3311 · Hydraulic & Pneumatic
Theme 2 · The fluid

Density

The most basic property of the oil — mass per unit volume. Small and almost constant, but it sets the oil's inertia and ties dynamic viscosity to the kinematic one.

Source: Rabie, Fluid Power Engineering, Ch. 2.

Before you start

What you need first

  • The oil's jobs (Topic 6).

What you'll be able to do

  • Use \(\rho=\dfrac{m}{V}\) both ways.
  • Quote a typical oil density and relative density.
  • Say why density matters and how it shifts with temperature.

Start here · the definition

Density = mass ÷ volume

$$\rho = \dfrac{m}{V}$$
where:
SymbolMeaningSI unit
\(\rho\)densitykg/m³
mmass of oilkg
Vvolume of oil
Hydraulic mineral oil is about \(\rho \approx 850\!-\!900~\text{kg/m}^3\) — a little lighter than water (1000 kg/m³). A handy round value is 870 kg/m³.

Relative density (specific gravity)

Relative density compares the oil with water — useful because it is dimensionless:

$$\text{RD} = \dfrac{\rho_{\text{oil}}}{\rho_{\text{water}}}$$
For \(\rho_{\text{oil}}=870\) and \(\rho_{\text{water}}=1000\), \(\text{RD}=0.87\). That is why oil floats on water — handy to remember when water contaminates a tank: it sinks to the bottom, where the drain is.

Why density matters

  • It sets the kinematic viscosity — \(\nu=\mu/\rho\) (Topic 9) and so the Reynolds number \(\mathrm{Re}=vD/\nu\) later.
  • It is the oil's inertia — a fast-reversing column of oil has mass that must be accelerated and stopped; denser oil resists more.
  • It sets the pressure of a standing oil column — the "head." A column of oil of height \(h\) presses down at its base with \(p=\rho g h\) (here \(g=9.81~\text{m/s}^2\) is gravity and \(h\) is the column height in metres). That column-pressure is what engineers call the head; denser oil gives more of it, which matters at the pump suction.

Density falls a little as the oil heats

Heat the oil and it expands, so the same mass fills more volume — density drops (roughly 0.6–0.7% per 10 °C for mineral oil). The change is small, but real.

Because density barely moves while viscosity changes a lot with temperature (Topic 9), it is the viscosity — not the density — that dominates how oil behaves across the working range. We treat the expansion itself in Topic 11.

✏️ Try it yourself — no numbers needed

Two oils have the same dynamic viscosity \(\mu\), but oil A is denser than oil B. Which has the higher kinematic viscosity \(\nu\), and which would turn turbulent at a lower speed?

Higher ν: oil B (the lighter one). Since \(\nu=\mu/\rho\), a smaller \(\rho\) gives a larger \(\nu\) for the same \(\mu\). Turbulent sooner: oil A (the denser one) has the lower \(\nu\), so \(\mathrm{Re}=vD/\nu\) is larger — it reaches the turbulent threshold at a lower speed.

Common mistakes to avoid

MistakeFix
Using water's density (1000) for oil Oil is lighter — about 870 kg/m³.
Quoting volume in litres inside \(\rho=m/V\) Convert to m³ first: \(1~\text{L}=10^{-3}~\text{m}^3\).
Expecting density to swing like viscosity Density changes only slightly with temperature; viscosity changes a lot.

Recap — the whole topic on one screen

$$\rho=\dfrac{m}{V}\qquad \rho_{\text{oil}}\approx 870~\text{kg/m}^3\qquad \text{RD}=\dfrac{\rho_{\text{oil}}}{\rho_{\text{water}}}\approx 0.87$$
IdeaWhat you own now
Density\(\rho=m/V\); oil ≈ 870 kg/m³ (lighter than water)
Relative density≈ 0.87 → oil floats on water
Why it mattersSets \(\nu=\mu/\rho\), inertia, and head

Next topic

Kinematic viscosity & oil grading

Now that you have both \(\mu\) and \(\rho\), we combine them into the kinematic viscosity \(\nu=\mu/\rho\) — the one datasheets quote, and how oil is graded and chosen.

→ Kinematic viscosity & oil grading