ME3311 · Hydraulic & Pneumatic
Theme 2 · The fluid
Density
The most basic property of the oil — mass per unit volume. Small and almost constant, but it sets the oil's inertia and ties dynamic viscosity to the kinematic one.
Source: Rabie, Fluid Power Engineering, Ch. 2.
Before you start
What you need first
- The oil's jobs (Topic 6).
What you'll be able to do
- Use \(\rho=\dfrac{m}{V}\) both ways.
- Quote a typical oil density and relative density.
- Say why density matters and how it shifts with temperature.
Start here · the definition
Density = mass ÷ volume
$$\rho = \dfrac{m}{V}$$
| Symbol | Meaning | SI unit |
|---|---|---|
| \(\rho\) | density | kg/m³ |
| m | mass of oil | kg |
| V | volume of oil | m³ |
Hydraulic mineral oil is about \(\rho \approx 850\!-\!900~\text{kg/m}^3\) — a
little lighter than water (1000 kg/m³). A handy round value is 870 kg/m³.
Relative density (specific gravity)
Relative density compares the oil with water — useful because it is dimensionless:
$$\text{RD} = \dfrac{\rho_{\text{oil}}}{\rho_{\text{water}}}$$
For \(\rho_{\text{oil}}=870\) and \(\rho_{\text{water}}=1000\),
\(\text{RD}=0.87\). That is why oil floats on water — handy to remember when
water contaminates a tank: it sinks to the bottom, where the drain is.
Why density matters
- It sets the kinematic viscosity — \(\nu=\mu/\rho\) (Topic 9) and so the Reynolds number \(\mathrm{Re}=vD/\nu\) later.
- It is the oil's inertia — a fast-reversing column of oil has mass that must be accelerated and stopped; denser oil resists more.
- It sets the pressure of a standing oil column — the "head." A column of oil of height \(h\) presses down at its base with \(p=\rho g h\) (here \(g=9.81~\text{m/s}^2\) is gravity and \(h\) is the column height in metres). That column-pressure is what engineers call the head; denser oil gives more of it, which matters at the pump suction.
Density falls a little as the oil heats
Heat the oil and it expands, so the same mass fills more volume — density drops (roughly 0.6–0.7% per 10 °C for mineral oil). The change is small, but real.
Because density barely moves while viscosity changes a lot with temperature
(Topic 9), it is the viscosity — not the density — that dominates how oil behaves
across the working range. We treat the expansion itself in Topic 11.
✏️ Try it yourself — no numbers needed
Two oils have the same dynamic viscosity \(\mu\), but oil A is denser than oil B. Which has the higher kinematic viscosity \(\nu\), and which would turn turbulent at a lower speed?
Higher ν:
oil B (the lighter one). Since \(\nu=\mu/\rho\), a smaller \(\rho\) gives a larger
\(\nu\) for the same \(\mu\).
Turbulent sooner:
oil A (the denser one) has the lower \(\nu\), so \(\mathrm{Re}=vD/\nu\) is larger — it reaches
the turbulent threshold at a lower speed.
Common mistakes to avoid
| Mistake | Fix |
|---|---|
| Using water's density (1000) for oil | Oil is lighter — about 870 kg/m³. |
| Quoting volume in litres inside \(\rho=m/V\) | Convert to m³ first: \(1~\text{L}=10^{-3}~\text{m}^3\). |
| Expecting density to swing like viscosity | Density changes only slightly with temperature; viscosity changes a lot. |
Recap — the whole topic on one screen
$$\rho=\dfrac{m}{V}\qquad
\rho_{\text{oil}}\approx 870~\text{kg/m}^3\qquad \text{RD}=\dfrac{\rho_{\text{oil}}}{\rho_{\text{water}}}\approx 0.87$$
| Idea | What you own now |
|---|---|
| Density | \(\rho=m/V\); oil ≈ 870 kg/m³ (lighter than water) |
| Relative density | ≈ 0.87 → oil floats on water |
| Why it matters | Sets \(\nu=\mu/\rho\), inertia, and head |