Dynamic viscosity & shear
"Thickness" is the oil's most important property. Here is what viscosity really is — the oil's resistance to being sheared — and the simple law that measures it.
Source: Rabie, Fluid Power Engineering, Ch. 2.
Before you start
What you need first
- The oil's jobs — lubricating and sealing depend on "thickness" (Topic 6).
What you'll be able to do
- Say what viscosity physically is.
- Use Newton's law \(\tau = \mu\,\dfrac{du}{dy}\).
- Read dynamic viscosity \(\mu\) and its units.
Start here · the idea
What is viscosity?
Viscosity is the oil's resistance to flowing — its internal friction. Honey has high viscosity (it resists, pours slowly); water has low viscosity (it flows freely).
Shearing the oil between two surfaces
Put oil between a fixed surface and a moving one. The oil sticks to both (the "no-slip" rule), so its speed grows smoothly from zero at the fixed wall to U at the moving wall.
That change of speed across the gap is the velocity gradient, \(\dfrac{du}{dy}\). Dragging one layer of oil over the next is what viscosity resists.
Newton's law of viscosity
To keep the top plate moving you must keep pushing it sideways, and the oil drags back along the surface with an equal force. Spread that sideways force over the contact area and you get the shear stress \(\tau\) — the drag force per unit area, measured in pascals (Pa). It is just like pressure, except pressure pushes into a surface while shear stress acts along it.
Newton's result is that this shear stress is proportional to the velocity gradient, and the constant of proportionality is the viscosity:
| Symbol | Meaning | SI unit |
|---|---|---|
| \(\tau\) | shear stress (drag per unit area) | Pa |
| \(\mu\) | dynamic (absolute) viscosity | Pa·s |
| \(\dfrac{du}{dy}\) | velocity gradient across the gap | 1/s |
A note on the units of \(\mu\)
The SI unit is the pascal-second (Pa·s). The old workshop units are the poise and centipoise:
✏️ Try it yourself — no numbers needed
A plate slides over an oil film at a fixed speed. You then make the film half as thick (same plate, same speed, same oil). What happens to the drag (shear stress) — and why?
Common mistakes to avoid
| Mistake | Fix |
|---|---|
| Using speed \(U\) where the law wants the gradient | Newton's law uses \(du/dy=U/h\) — divide by the gap. |
| Leaving \(\mu\) in centipoise | Convert to Pa·s first: \(1~\text{cP}=10^{-3}~\text{Pa·s}\). |
| Confusing \(\mu\) with \(\nu\) | \(\mu\) is dynamic viscosity; the kinematic one \(\nu=\mu/\rho\) comes a little later (after density). |
Recap — the whole topic on one screen
| Idea | What you own now |
|---|---|
| Viscosity | The oil's resistance to being sheared (internal friction) |
| Newton's law | \(\tau=\mu\,du/dy\) — stress ∝ velocity gradient |
| Dynamic viscosity \(\mu\) | The proportionality constant, in Pa·s |